FAR-FARMAKOGNOSI DIAH GASAL 23/24: Forum kelas pagi

Assalamualaikum wr.wb
apa kabar mahasiswa ? semoga sehat selalu ya..
silahkan teman2 membaca materi dan menonton video yang telah disediakan ya.
kemudian silahkan teman2 diskusi di forum ini. serta menjawab pertanyaan yang sy berikan ya.

selamat belajar.

Re: Forum kelas pagi

by DIAH RATNASARI - Tuesday, 31 October 2023, 7:50 AM

Studi kasus 1 :
TTK melakukan uji kadar air simplisia rimpang Curcuma domestica. Bobot awal simplisia 1,0086 g. Bobot cawan + simplisia awal 46, 4420 g lalu dipanaskan di oven dan didapat bobot setelah pemanasan 46,3575 g.

Berapa % kadar air dari simplisia tersebut ?

Re: Forum kelas pagi

by KURNIA LINTANG SARASWATI - Tuesday, 31 October 2023, 8:27 AM

% Kadar Air = [(W1 - W2) / W1] x 100%

Diketahui:

W1 = 1,0086 g
W2 = 46,3575 g - 46,4420 g = -0,0845 g

jawab:

% Kadar Air = [(1,0086 g - (-0,0845 g)) / 1,0086 g] x 100%
% Kadar Air = [(1,0086 g + 0,0845 g) / 1,0086 g] x 100%
% Kadar Air = (1,0931 g / 1,0086 g) x 100%
% Kadar Air ≈ 108,035%

Re: Forum kelas pagi

by DIAH RATNASARI - Tuesday, 31 October 2023, 8:43 AM

kurang tepat

Re: Forum kelas pagi

by KURNIA LINTANG SARASWATI - Tuesday, 31 October 2023, 8:51 AM

% kadar air = W1 - (W2-W0)/W1 x 100%

Diketahui

W1 = 1,0086 g
W0 = 46,4420 g - 1,0086 g
W2 = 46,3575 g

Jawab :

% Kadar Air =1,0086 g - (46,3575 g - 45,4334 g)/ 1,0086 g x 100%
% Kadar Air= 1,0086 g -0,9241 g/ 1,0086 g x 100%
% Kadar Air= 0,0845 g / 1,0086 g x 100%
% Kadar air = 8,4%

Re: Forum kelas pagi

by LINDAH ISNA ZULFIYANA - Tuesday, 31 October 2023, 8:36 AM

Diket :
W1 = 1,0086 g
W0 = 46,4420 g - 1,0086 g
W2 = 46,3575 g
Ditanya :
% kadar air ?
Jawab :
% kadar air = W1 - (W2-W0)/W1 x 100%
=1,0086 g - (46,3575 g - 45,4334 g)/ 1,0086 g x 100%
= 1,0086 g -0,9241 g/ 1,0086 g x 100%
=0,0845 g / 1,0086 g x 100%
=0,084 x 100%
=8,4%

Re: Forum kelas pagi

by DIAH RATNASARI - Tuesday, 31 October 2023, 8:43 AM

oke. benar

Re: Forum kelas pagi

by NELITA DWI NOVIYANTI - Tuesday, 31 October 2023, 8:41 AM

diketahui :
W0 = 46,4420 - 1,0086 = 45,4334 gram
W1 = 1,0086 gram
W2 = 46,3575 gram

ditanya = % kadar air dari simplisia

jawab =
kadar air (%) = W1 - (W2-W0) / W1 × 100%
kadar air (%) = 1,0086 g - (46,3575 g - 45,4334 g) / 1,0086 g × 100%
kadar air (%) = 1,0086 g - 0,9241 g / 1,0086 g × 100%
kadar air (%) = 0,0845 / 1,0086 × 100%
kadar air (%) = 0,084 × 100%
= 8,4%

Re: Forum kelas pagi

by DIAH RATNASARI - Tuesday, 31 October 2023, 8:45 AM

oke. benar

Re: Forum kelas pagi

by ZURROIDAH ARIF VANNY - Tuesday, 31 October 2023, 8:43 AM

% kadar air = W1 - (W2-W0)/W1 x 100%

% kadar air =1,0086 g - (46,3575 g - 45,4334 g)/ 1,0086 g x 100%
% kadar air = 1,0086 g -0,9241 g/ 1,0086 g x 100%
% kadar air =0,0845 g / 1,0086 g x 100%
% kadar air =0,084 x 100%
% kadar air =8,4%

Re: Forum kelas pagi

by DIAH RATNASARI - Tuesday, 31 October 2023, 8:45 AM

sip

Re: Forum kelas pagi

by NADYA RAMADHANTI - Tuesday, 31 October 2023, 8:45 AM

Diketahui:
W1 = 1,0086 gram
W0 = 46,4420 gram - 1,0086 gram = 45,4334 gram
W2 = 46,3575 gram

Dijawab :
% kadar = W1 - (W2-W0) : W1 x 100%
= 1,0086 g - (46,3575 g - 45,4334 g) : 1,0086 g x 100%
= 1,0086 g - 0,9241 g : 1,0086 g x 100 %
= 0,0845 g : 1,0086 g x 100%
= 0,08377 g x 100%
= 0,084 g x 100%
= 8,4 %
Maka kadar air = 8,4 %

Re: Forum kelas pagi

by AULIYA DWI INDRIANI - Tuesday, 31 October 2023, 8:48 AM

Diketahui :
W1 = 1,0086 g
W0 = 46,4420 g - 1,0086 g
W2 = 46,3575 g

Ditanya :
% kadar air ?

dijawab :
% kadar air = W1 - (W2-W0)/W1 x 100%

maka:
=1,0086 g - (46,3575 g - 45,4334 g)/ 1,0086 g x 100%
= 1,0086 g -0,9241 g/ 1,0086 g x 100%
=0,0845 g / 1,0086 g x 100%
=0,084 x 100%
=8,4%
jadi % kadar dari simplisia tersebut adalah 8,4%

Re: Forum kelas pagi

by ARINA AZAM MUSAADAH - Tuesday, 31 October 2023, 8:53 AM

Studi kasus 1
Diketahui:
● Bobot cawan + simplisia awal= 46,4420 g
● W1= 1,0086 g
● W2= 46,3575 g
● W0= 46,4420 g - 1,0086 g

- Ditanya= % Kadar air=...?
- Jawab=
% Kadar air = W1- (W2 - W0) / W1 × 100%
% Kadar air = 1,0086 - (46,3575 - 45,4334) / 1,0086 × 100%
% Kadar air = 1,0086 - 0,9241 / 1,0086 × 100%
%Kadar air = 0,0845/1,0086 × 100%
% Kadar air = 8,378 %

Re: Forum kelas pagi

by SASTI AMILIA PUTRI - Tuesday, 31 October 2023, 8:54 AM

Diketahui:
W1 = 1,0086 g
W0 = 46,4420 g - 1,0086 g = 45,4334 g
W2 = 46,3575 g

Ditanya :
berapa % kadar air ?

Dijawab :
% kadar = W1 - (W2-W0) / W1 x 100%

= 1,0086 g - (46,3575 g - 45,4334 g) / 1,0086 g x 100%

= 1,0086 g - 0,9241 g / 1,0086 g x 100 %

= 0,0845 g / 1,0086 g x 100%

= 0,08377 g x 100%

= 0,084 g x 100%

= 8,4 %
Maka jumlah kadar air adalah 8,4 %

Re: Forum kelas pagi

by INDAH MARYAM HAMSAH - Tuesday, 31 October 2023, 8:57 AM

Diket:
W1 = 1,0086 g
W0 = 46,4420 g - 1,0086 g = 45,4334 g
W2 = 46,3575
Ditanya = kadar air (%) simplisia

Dijawab =
% kadar air= W1 - (W2-W0) / W1 × 100%
% kadar air = 1,0086 g - (46,3575 g - 45,4334 g) / 1,0086 g × 100%
% kadar air = 1,0086 g - 0,9241 g / 1,0086 g × 100%
% kadar air = 0,0845 / 1,0086 × 100%

=0,08377 g x 100%

= 0,084 g x 100%

= 8,4% (kadar air dari simplisia tersebut)

Re: Forum kelas pagi

by NURUL HIDAYAH - Tuesday, 31 October 2023, 8:58 AM

Diket =
W1 = 1,0086 g
W2 = 46,3575 g
W0 = ?
~Bobot cawan + simplisia awal = 46,4420 g
>Ditanya = kadar air ?
Jawab =
>Kadar air = W1 - (W2- W0 )/ W1 x 100%
= 1,0086 - (46,3575 - 45,4334)/ 1,0086 x 100%
= 1,0086 - 0,9241/ 1,0086 x 100%
= 00,84/ 1,0085 x 100%
= 8,378%

Re: Forum kelas pagi

by FANNY DALMAYANTI - Tuesday, 31 October 2023, 8:59 AM

1. diketahui
W1 = 1,0086 g
W0 = 46,4420 g - 1,0086 g
W2 = 46,3575 g

Jawab :
% kadar air = W1 - (W2-W0)/W1 x 100%
% Kadar Air =1,0086 g - (46,3575 g - 45,4334 g)/ 1,0086 g x 100%
% Kadar Air= 1,0086 g -0,9241 g/ 1,0086 g x 100%
% Kadar Air= 0,0845 g / 1,0086 g x 100%
% Kadar air = 8,4%

Re: Forum kelas pagi

by NURUSSA'ADAAH NURUSSA'ADAAH - Tuesday, 31 October 2023, 9:00 AM

Diket :
w1 = 1,0086 g
W2 = 46,3575 g
W0 = 45,4334 g

Ditanya : % kadar air?

Jawab :
Kadar air (% wet basis) = W1- (W2 - W0)/W1 × 100% =
1,0086 g - (46,3575 g - 45,4334)/1,0086 g × 100% =
1,0086 g - 0,9241 g/1,0086 g × 100% =
0,0845/1,0086 × 100% =
0,084 × 100% = 8,4 %

Re: Forum kelas pagi

by ZELVIANA FREANDA - Tuesday, 31 October 2023, 9:17 AM

Re: Forum kelas pagi

by FITRI ARTHA APRILLIA - Tuesday, 31 October 2023, 9:19 AM

1. diketahui
W1 = 1,0086 g
W0 = 46,4420 g - 1,0086 g
W2 = 46,3575 g
Jawab :
% kadar air = W1 - (W2-W0)/W1 x 100%
% Kadar Air =1,0086 g - (46,3575 g - 45,4334 g)/ 1,0086 g x 100%
% Kadar Air= 1,0086 g -0,9241 g/ 1,0086 g x 100%
% Kadar Air= 0,0845 g / 1,0086 g x 100%
% Kadar air = 8,4%

Re: Forum kelas pagi

by MUSTIKA ARRAUF HAKIM - Tuesday, 31 October 2023, 9:22 AM

Diketahui :

W1 = 1,0086 g
W0 = 46,4420 g - 1,0086 g
W2 = 46,3575 g

Ditanya :
% kadar air ?

Jawab :

% kadar air = W1 - (W2-W0)/W1 x 100%
=1,0086 g - (46,3575 g - 45,4334 g)/ 1,0086 g x 100%
= 1,0086 g -0,9241 g/ 1,0086 g x 100%
=0,0845 g / 1,0086 g x 100%
=0,084 x 100%
=8,4%
Jadi jumlah kadar air adalah 8,4%

Re: Forum kelas pagi

by NIKEN LARAS OKTAVIARY - Tuesday, 31 October 2023, 9:25 AM

Diketahui:
Bobot awal simplisia (W1)= 1,0086 g
Bobot cawan + simplisia awal= 46,4420 g
Bobot cawan (W0)= 46,4420-1,0086= 45,4334 g
Bobot akhir (W2)= 46,3575 g
Dicari:
% kadar air
Jawab:
%kadar air=[W2-W0/W1 × 100/20] × 100%
= [46,3575-45,4334/1,0086 × 100/20] × 100%
= 4,58%

Re: Forum kelas pagi

by IRANI AGUSTIN - Tuesday, 31 October 2023, 9:26 AM

Diket
W0: 46,4420 g - 1,0086 g
W1 : 1,0086 g
W2 : 46,3575 g
Bobot cawan + simplisia awal : 46,4420 g

Ditanya : berapa% kadar air simplisia ?

Jawab :
Kadar air
: w1- ( w2-w0) ÷ w1 × 100%
: 1,0086 g - (46,3575 - 45,4334) ÷ 1,0086 × 100%
: 1,0086 - 0,9241 ÷ 1,0086 × 100%
: 0,0845 ÷ 1,0086 × 100%
: 8, 378% ( 8,4%)
kadar air = 8,4%

Re: Forum kelas pagi

by ALIFFIA RAGIL FITRIANI - Tuesday, 31 October 2023, 9:38 AM

Re: Forum kelas pagi

by SITI ANIS JANNATIN - Tuesday, 31 October 2023, 9:40 AM

Diket :

w1 = 1,0086 g
W2 = 46,3575 g
W0 = 45,4334 g

Ditanya : % kadar air?

Jawab :

Kadar air (% wet basis) = W1- (W2 - W0)/W1 × 100% =
1,0086 g - (46,3575 g - 45,4334)/1,0086 g × 100% =
1,0086 g - 0,9241 g/1,0086 g × 100% =
0,0845/1,0086 × 100% =
0,084 × 100% = 8,4 %

Re: Forum kelas pagi

by PUTRI NANDA SAFILATURROHMAH - Tuesday, 31 October 2023, 9:43 AM

% kadar air = W1 - (W2-W0)/W1 x 100%
% kadar air =1,0086 g - (46,3575 g - 45,4334 g)/ 1,0086 g x 100%
% kadar air = 1,0086 g -0,9241 g/ 1,0086 g x 100%
% kadar air =0,0845 g / 1,0086 g x 100%
% kadar air =0,084 x 100%
% kadar air =8,4%
maka jumlah kadar air adalah 8,4%

Re: Forum kelas pagi

by NIMAS KUSUMANING AYU INDAH PERMADANI - Tuesday, 31 October 2023, 9:48 AM

Diketahui :
W1 = 1,0086 g
W0 = 46,4420 g - 1,0086 g
W2 = 46,3575 g

Ditanya :
% Kadar air ?

Jawab :
% Kadar air = W1 - (W2-W0)/W1 x 100%
% Kadar air = 1,0086 g - (46,3575 g-45,4334 g) / 1,0086 g x 100%
% Kadar air = 1,0086 g - 0,9241 g / 1,0086 g x 100%
% Kadar air = 0,0845 g / 1,0086 g x 100%
% Kadar air = 0,084 x 100%
% Kadar air = 8,4%

Jadi, kadar air dari simplisia rimpang Curcuma domestica ialah 8,4%

Re: Forum kelas pagi

by DANU PRASTIYO - Tuesday, 31 October 2023, 10:05 AM

Re: Forum kelas pagi

by Luti ANA - Tuesday, 31 October 2023, 10:07 AM

diketahui :
W0 = 46,4420 - 1,0086 = 45,4334 gram
W1 = 1,0086 gram
W2 = 46,3575 gram

ditanya = % kadar air simplisia

jawab =
kadar air (%) = W1 - (W2-W0) / W1 × 100%
= 1,0086 g - (46,3575 g - 45,4334 g) / 1,0086 g × 100%
= 1,0086 g - 0,9241 g / 1,0086 g × 100%
= 0,0845 / 1,0086 × 100%
= 0,084 × 100%
= 8,4%
Jadi % kadar air dari simplisia rimpang Curcuma sebesar 8,4%

Re: Forum kelas pagi

by DANU PRASTIYO - Tuesday, 31 October 2023, 10:08 AM

Re: Forum kelas pagi

by LIESTYA NUR AZIZAH - Tuesday, 31 October 2023, 10:11 AM

Diketahui :
W1 = 1,0086 g
W0 = 46,4420 g - 1,0086 g = 45,4334 g
W2 = 46,3575 g

% Kadar air = W1 - (W2-W0)/W1 × 100%
% Kadar air = 1,0086 - (46,3575-45,4334)/1,0086 × 100%
% Kadar air = 1,0086 - 0,9241/1,0086 × 100%
% Kadar air = 0,0845/1,0086 × 100%
% Kadar air = 0,084 × 100%
% Kadar air = 8,4%

Re: Forum kelas pagi

by DIAH RATNASARI - Tuesday, 31 October 2023, 7:53 AM

Serbuk simplisia daun Tapak liman ditimbang sebnayak 5 gram, dimasukan ke erlenmeyer dan ditambah 100 ml etanol 95% diaduk selama 6 jam kemudian dibiarkan selama 18 jam. setelah penyaringan dan filtrat yang didapat diuapkan hingga bobot tetap. Diketahui bobot cawan kosong 29,67 gram; cawan dan ekstrak 29,85 gram.

Berapa persen kadar sari larut etanol yang diperoleh ?

Re: Forum kelas pagi

by KURNIA LINTANG SARASWATI - Tuesday, 31 October 2023, 8:40 AM

% Kadar Sari Larut Etanol = [(W2 - W0) / W1] x 100%

Diketahui:

W0 = 29,67 gram
W2 = 29,85 gram
W1 (serbuk simplisia daun Tapak liman) = 5 gram

jawab:

% Kadar Sari Larut Etanol = [(29,85 g - 29,67 g) / 5 g] x 100%
% Kadar Sari Larut Etanol = (0,18 g / 5 g) x 100%
% Kadar Sari Larut Etanol = 3.6%

Re: Forum kelas pagi

by DIAH RATNASARI - Tuesday, 31 October 2023, 8:47 AM

oke. benar

Re: Forum kelas pagi

by ZURROIDAH ARIF VANNY - Tuesday, 31 October 2023, 8:49 AM

% kadar sari larut etanol = bobot cawan dan ekstrak -Wo /W1 × 100%

= 29,85g-29,67g /5g ×100%
= 0,18g/5g ×100%
= 3,6 %

Re: Forum kelas pagi

by AULIYA DWI INDRIANI - Tuesday, 31 October 2023, 8:52 AM

Diketahui:
W0 = 29,67 gram
W2 = 29,85 gram
W1 (serbuk simplisia daun Tapak liman) = 5 gram

ditanya:
%Kadar sari laut etanol

jawab:
% Kadar Sari Larut Etanol = [(W2 - W0) / W1] x 100%

maka:
% Kadar Sari Larut Etanol = [(29,85 g - 29,67 g) / 5 g] x 100%
% Kadar Sari Larut Etanol = (0,18 g / 5 g) x 100%
% Kadar Sari Larut Etanol = 3,6%
# Jadi %Kadar sari laut etanol yang diperoleh adalah 3,6%

Re: Forum kelas pagi

by ZELVIANA FREANDA - Tuesday, 31 October 2023, 8:53 AM

simplisia : 5gr
vol pelarut : 100 ml
cawan kosong : 29,67 gr
cawan + ekstrak : 29,85 gr

bobot sari =
29,85 - 29.67 = 0.18 gr

bobot sari total =
100/100 x 0.18 g = 0.18 g

% = 0.18 g / 5 g x 100%
= 3,6%

Re: Forum kelas pagi

by NADYA RAMADHANTI - Tuesday, 31 October 2023, 8:58 AM

Diketahui:
W0 = 29,67 gram
W1 = 5 gram
W2 = 29,85 gram

Dijawab:
% Kadar Sari Larut Etanol = (W2 - W0) / W1 x 100%
% Kadar Sari Larut Etanol = (29,85 g - 29,67 g) / 5 g x 100%
% Kadar Sari Larut Etanol = 0,18 g / 5 g x 100%
% Kadar Sari Larut Etanol = 3,6 %
Maka kadar sari larut etanol = 3,6 %

Re: Forum kelas pagi

by LINDAH ISNA ZULFIYANA - Tuesday, 31 October 2023, 8:59 AM

Diket :
W0 = 29,67 g
W1 = 5 g (serbuk simplisia daun Tapak liman)
W2 = 29,85 g

Ditanya :
Persen kadar sari larut etanol ?

Jawab :
% Kadar Sari Larut Etanol = [(W2-W0)/W1] x 100%
= [29,85 g - 29,67 g)/ 5 g] x 100%
= 0,18 g/ 5 g x 100%
= 3,6 %

Re: Forum kelas pagi

by NELITA DWI NOVIYANTI - Tuesday, 31 October 2023, 9:00 AM

diketahui :
W0 = 29,67 gram
W1 = 5 gram
W2 = 29,85 gram

ditanya : % kadar sari larut etanol yg diperoleh?

jawab :
kadar sari larut etanol (%) = (29,85 g - 29,67 g) / 5 g x 100%
kadar sari larut etanol (%) =
(0,18 g) / 5 g x 100%
kadar sari larut etanol (%) =
3,6%

Re: Forum kelas pagi

by FANNY DALMAYANTI - Tuesday, 31 October 2023, 9:02 AM

Diketahui:
W0 = 29,67 gram
W2 = 29,85 gram
W1 (serbuk simplisia daun Tapak liman) = 5 gram
Jawab:
% Kadar Sari Larut Etanol = [(W2 - W0) / W1] x 100%
% Kadar Sari Larut Etanol = [(29,85 g - 29,67 g) / 5 g] x 100%
% Kadar Sari Larut Etanol = (0,18 g / 5 g) x 100%
% Kadar Sari Larut Etanol = 3,6%

Re: Forum kelas pagi

by ARINA AZAM MUSAADAH - Tuesday, 31 October 2023, 9:05 AM

Diketahui=
Wo = 29,67 g
W1= 5 g
W2 = 29,85 g

Ditanya=
% Kadar sari larut etanol= ....??

Jawab=
% Kadar sari larut etanol= W2 - Wo / W1 × 100%
% Kadar sari larut etanol= 29,85 - 29 67 / 5 × 100%
% Kadar sari larut etanol= 0,18 / 5 × 100%
% Kadar sari larut etanol= 0,036 × 100%
% Kadar sari larut etanol= 3,6 %

Re: Forum kelas pagi

by SASTI AMILIA PUTRI - Tuesday, 31 October 2023, 9:06 AM

Diketahui:
W0 = 29,67 g
W1 = 5 gram ( serbuk simplisia daun tapak liman )
W2 = 29,85 g

Ditanya :
berapa % kadar sari laut etanol ?

Dijawab:
% Kadar Sari Larut Etanol =
[(W2 - W0) / W1] x 100%

= [(29,85 g - 29,67 g) / 5 g] x 100%

= (0,18 g / 5 g) x 100%

= 3,6%
maka % kadar sari larut etanol adalah 3,6 %

Re: Forum kelas pagi

by NURUL HIDAYAH - Tuesday, 31 October 2023, 9:06 AM

Diket =
W1 = 5 g
W2= 29,85 g
W0 = 29, 67 g
Ditanya = kadar sari ?
Jawab =
% kadar sari laut etanol = W2- W0/ W1
= 29,85-29,67/5 x 100%
= 0,18/5 x 100%
= 0,036 x 100%
= 3,6 %

Re: Forum kelas pagi

by INDAH MARYAM HAMSAH - Tuesday, 31 October 2023, 9:14 AM

Diketahui :

W1 = 5 g

W2 = 29,85 g
W0 = 29,67 gram
Ditanya : % kadar sari larut etanol yg diperoleh?

Dijawab :
% kadar sari laut etanol= (29,85 g - 29,67 g) / 5 g x 100%
% kadar sari laut etanol =
(0,18 g / 5 g) x 100%
Jadi % kadar sari laut etanol =
3,6%

Re: Forum kelas pagi

by FITRI ARTHA APRILLIA - Tuesday, 31 October 2023, 9:24 AM

Diketahui:
W0 = 29,67 gram
W2 = 29,85 gram
W1 (serbuk simplisia daun Tapak liman) = 5 gram
% Kadar Sari Larut Etanol = [(W2 - W0) / W1] x 100%
% Kadar Sari Larut Etanol = [(29,85 g - 29,67 g) / 5 g] x 100%
% Kadar Sari Larut Etanol = (0,18 g / 5 g) x 100%
% Kadar Sari Larut Etanol = 3,6%

Re: Forum kelas pagi

by NURUSSA'ADAAH NURUSSA'ADAAH - Tuesday, 31 October 2023, 9:25 AM

Diket :
W0 = 29,67 gram
W1 = 5 gram
W2 = 29,85 gram

Ditanya : %Kadar sari laut etanol?

Jawab :
% Kadar Sari Larut Etanol = (W2 - W0) /W1 x 100%=
(29,85 gram - 29,67 gram) /5 gram x 100% = (0,18 gram / 5 gram) x 100% = 3.6%

Jadi, persentase kadar sari larut etanol yang diperoleh adalah sekitar 3.6%.

Re: Forum kelas pagi

by NIKEN LARAS OKTAVIARY - Tuesday, 31 October 2023, 9:28 AM

Diketahui:
Bobot cawan kosong (W0)= 29,67 g
Bobot cawan dan ekstrak (W2) = 29,85 g
Bobot ekstrak(W1)= 5 g

Dicari:
%kadar sari lar. etanol

Jawab:
%kadar sari lar. etanol =[W2-W0/W1] × 100%
= [29,85-29,67/5] × 100%
= 3,6%

Re: Forum kelas pagi

by IRANI AGUSTIN - Tuesday, 31 October 2023, 9:33 AM

% Kadar Sari Larut Etanol = [(W2 - W0) / W1] x 100%

Diketahui:
W0 = 29,67 gram
W2 = 29,85 gram
W1 (serbuk simplisia daun Tapak liman) = 5 gram

jawab:
% Kadar Sari Larut Etanol
= (W2 - W0) / W1 x 100%
= [(29,85 g - 29,67 g) / 5 g] x 100%
= (0,18 g / 5 g) x 100%
= 3.6% Kadar Sari Larut Etanol

Re: Forum kelas pagi

by MUSTIKA ARRAUF HAKIM - Tuesday, 31 October 2023, 9:36 AM

Diketahui:

W0 = 29,67 gram
W2 = 29,85 gram
W1 ( serbuk simplisia daun Tapak liman ) = 5 gram

Ditanya:

%Kadar sari laut etanol ?

jawab:

% Kadar Sari Larut Etanol = [(W2 - W0) / W1] x 100%
% Kadar Sari Larut Etanol = [(29,85 g - 29,67 g) / 5 g] x 100%
% Kadar Sari Larut Etanol = (0,18 g / 5 g) x 100%
% Kadar Sari Larut Etanol = 3,6%

Re: Forum kelas pagi

by ALIFFIA RAGIL FITRIANI - Tuesday, 31 October 2023, 9:40 AM

Re: Forum kelas pagi

by SITI ANIS JANNATIN - Tuesday, 31 October 2023, 9:42 AM

Diket :

W0 = 29,67 gram
W1 = 5 gram
W2 = 29,85 gram

Ditanya : %Kadar sari laut etanol?

Jawab :

% Kadar Sari Larut Etanol = (W2 - W0) /W1 x 100%=
(29,85 gram - 29,67 gram) /5 gram x 100% = (0,18 gram / 5 gram) x 100% = 3.6%

Jadi, persentase kadar sari larut etanol yang diperoleh adalah sekitar 3.6%.

Re: Forum kelas pagi

by PUTRI NANDA SAFILATURROHMAH - Tuesday, 31 October 2023, 9:45 AM

Diketahui:
W0 = 29,67 gram
W1 = 5 gram
W2 = 29,85 gram
jawab:
% Kadar Sari Larut Etanol = (W2 - W0) / W1 x 100%
% Kadar Sari Larut Etanol = (29,85 g - 29,67 g) / 5 g x 100%
% Kadar Sari Larut Etanol = 0,18 g / 5 g x 100%
% Kadar Sari Larut Etanol = 3,6 %
Maka kadar sari larut etanol = 3,6 %

Re: Forum kelas pagi

by NIMAS KUSUMANING AYU INDAH PERMADANI - Tuesday, 31 October 2023, 9:53 AM

Diketahui :

W0 = 29,67 gram
W1 = 5 gram
W2 = 29,85 gram

Ditanya :
%Kadar sari laut etanol?

Jawab :

% Kadar Sari Larut Etanol = (W2 - W0) /W1 x 100%
= (29,85 gram - 29,67 gram) /5 gram x 100%
= (0,18 gram / 5 gram) x 100%
= 3.6%

Jadi, persentase kadar sari larut etanol yang diperoleh adalah sekitar 3.6%.

Re: Forum kelas pagi

by DANU PRASTIYO - Tuesday, 31 October 2023, 10:10 AM

Diket :

W0 = 29,67 gram
W1 = 5 gram
W2 = 29,85 gram

Ditanya : %Kadar sari laut etanol?

Jawab :

% Kadar Sari Larut Etanol = (W2 - W0) /W1 x 100%=
(29,85 gram - 29,67 gram) /5 gram x 100% = (0,18 gram / 5 gram) x 100% = 3.6%

Jadi, persentase kadar sari larut etanol yang diperoleh adalah sekitar 3.6%.

Re: Forum kelas pagi

by Luti ANA - Tuesday, 31 October 2023, 10:11 AM

diketahui :
W0 = 29,67 gram (bobot cawan kosong)
W1 = 5 gram ( berat simplisia)
W2 = 29,85 gram (cawan + ekstrak)

ditanya :
% kadar sari larut etanol ?

jawab :
kadar sari larut etanol (%) = (29,85 g - 29,67 g) / 5 g x 100%
=0,18 g / 5 g x 100%
=3,6%

Re: Forum kelas pagi

by LIESTYA NUR AZIZAH - Tuesday, 31 October 2023, 10:26 AM

Diketahui :
W0 = 29,67 g
W1 = 5 g
W2 = 29,85 g

% Kadar sari larut etanol = (W2-W0)/W1 × 100%
% Kadar sari larut etanol = (29,85-29,67)/5 × 100%
% Kadar sari larut etanol = 0,18/5 × 100%
% Kadar Sari larut etanol = 3,6 %

Re: Forum kelas pagi

by DIAH RATNASARI - Tuesday, 31 October 2023, 7:59 AM

TTK melakukan uji parameter standar salah satunya adalah penetapan kadar abu total dari daun steril kelakai. Hasil penimbangan didapatkan berat simplisia adalah 2 gram, berat cawan kosong adalah 37,3 gram, sedangkan berat cawan berisi abu adalah 37,82 gram.

Berapa persen kadar abu dari simplisia tersebut?

Re: Forum kelas pagi

by ZELVIANA FREANDA - Tuesday, 31 October 2023, 8:47 AM

cawan kosong = 37,3 gr
cawan + simplisia = 37,3 gr + 2gr = 39,3 gr
cawan + abu = 37,82 gr

jawab :
37,82 - 37,3 = 0.52
39, 3 - 37, 3 = 2

0.52/2 x 100% = 26%

Re: Forum kelas pagi

by ZURROIDAH ARIF VANNY - Tuesday, 31 October 2023, 8:53 AM

% kadar abu = Wo+abu berat cawan kosong /W1 ×100%

= 37,82g-37,3 g/2g×100%
= 0,52g/2g ×100%
= 26%

Re: Forum kelas pagi

by KURNIA LINTANG SARASWATI - Tuesday, 31 October 2023, 9:01 AM

% Kadar Abu = [(Berat Cawan + Abu - Berat Cawan Kosong) / Berat Simplisia] x 100%

Diketahui:

Berat Simplisia = 2 gram
Berat Cawan Kosong = 37,3 gram
Berat Cawan + Abu = 37,82 gram

Jawab:

% Kadar Abu = [(37,82 g - 37,3 g) / 2 g] x 100%
% Kadar Abu = (0,52 g / 2 g) x 100%
% Kadar Abu = 26%

Re: Forum kelas pagi

by AULIYA DWI INDRIANI - Tuesday, 31 October 2023, 9:04 AM

diketahui :
cawan kosong: 37,3 gram
cawan dan abu: 37,82 gram
bobot abu: 37,82-37,3 = 0,52

dijawab :
%kadar abu = 0,52/2 x 100%
= 26%

# Jadi %kadar abu dari simplisia adalah 26%

Re: Forum kelas pagi

by SASTI AMILIA PUTRI - Tuesday, 31 October 2023, 9:13 AM

Diketahui :
Berat Simplisia = 2 g
Berat Cawan Kosong = 37,3 g
Berat Cawan + Abu = 37,82 g

Ditanya :
berapa % kadar abu simplisia ?

Dijawab:
% Kadar Abu = [(Berat Cawan + Abu - Berat Cawan Kosong) / Berat Simplisia] x 100%

= % Kadar Abu = [(37,82 g - 37,3 g) / 2 g] x 100%

= (0,52 g / 2 g) x 100%

= 26%
maka % kadar abu adalah 26 %

Re: Forum kelas pagi

by FANNY DALMAYANTI - Tuesday, 31 October 2023, 9:19 AM

diketahui :
cawan kosong: 37,3 gram
cawan dan abu: 37,82 gram
bobot abu: 37,82-37,3 = 0,52

dijawab :
% kadar abu = 0,52/2 x 100%
= 26%

Re: Forum kelas pagi

by ARINA AZAM MUSAADAH - Tuesday, 31 October 2023, 9:20 AM

Diketahui=
Bobot sampel+ cawan = 37,82 g
Bobot cawan kosong = 37,3 g
Bobot sampel awal= 2 g

Ditanya= % Kadar abu=....?

Jawab=
% Kadar abu = bobot sampel+cawan - bobot cawan kosong / bobot sampel awal × 100%
% Kadar abu= 37,82 - 37,3 / 2 × 100%
% Kadar abu = 0,52/ 2 × 100%
% Kadar abu = 0,26 × 100%
% Kadar abu = 26 %

Re: Forum kelas pagi

by INDAH MARYAM HAMSAH - Tuesday, 31 October 2023, 9:28 AM

Diketahui :
Berat Cawan Kosong = 37,3 g
Berat Cawan + Abu = 37,82 g
Berat Simplisia = 2 g
Ditanya :
% kadar abu simplisia ?

Dijawab:
% Kadar Abu = (Berat Cawan + Abu - Berat Cawan Kosong) / Berat Simplisia) x 100%
= % Kadar Abu = (37,82 g - 37,3 g) / 2 g x 100%
= (0,52 g / 2 g) x 100%
= 26% (% kadar abu simplisia)

Re: Forum kelas pagi

by NIKEN LARAS OKTAVIARY - Tuesday, 31 October 2023, 9:29 AM

Diketahui:
Berat simplisia= 2 g
Berat cawan (W0)= 37,3 g
Berat cawan dan simplisia (W1)= 37,3 + 2= 39,5 g
Berat cawan dan abu (W2)= 37,82 g

Dicari:
% kadar abu

Jawab:
% kadar abu= berat abu (W2-W0)/berat simplisia (W1-W0) × 100%
=(37,82-37,3)/(39,3-37,3)×100%
= 0,26%

Re: Forum kelas pagi

by FITRI ARTHA APRILLIA - Tuesday, 31 October 2023, 9:35 AM

% kadar abu =37,82g-37,3g/2g×100%
= 0,52g/2g ×100%
= 26%

Re: Forum kelas pagi

by IRANI AGUSTIN - Tuesday, 31 October 2023, 9:36 AM

Diketahui=

Berat cawan dan simplisia (W1)= 37,3 + 2= 39,5 g
Bobot sampel+ cawan = 37,82 g
Bobot cawan kosong = 37,3 g
Bobot sampel awal= 2 g

Ditanya= % Kadar abu?

Jawab=
% Kadar abu
= bobot sampel+cawan - bobot cawan kosong / bobot sampel awal × 100%
= 37,82 - 37,3 / 2 × 100%
= 0,52/ 2 × 100%
= 0,26 × 100%
= 26 % Kadar abu

Re: Forum kelas pagi

by NURUL HIDAYAH - Tuesday, 31 October 2023, 9:36 AM

Diketahui=
Bobot sampel+ cawan = 37,82 g
Bobot cawan kosong = 37,3 g
Bobot sampel awal= 2 g

Ditanya= % Kadar abu=....?
Jawab =
% kadar abu = W1- W2/W
= bobot sampel + cawan - bobot cawan kosong / bobot sampel awal x 100%
= 37,82 g - 37,3 g/2g x 100%
= 0,52/2x 100%
= 0,26 x 100 %
= 26 %

Re: Forum kelas pagi

by LINDAH ISNA ZULFIYANA - Tuesday, 31 October 2023, 9:39 AM

Diket :
W0 = 37,3 g
W2 abu = 37,82 g
W1 sampel = 2 gram (simplisia)

Ditanya :
Persen kadar abu simplisia tersebut?

Jawab:
% kadar abu = berat abu (W2-W0)/ berat sampel x 100%
= 37,82 g - 37,3 g / 2g x 100%
= 0,52 g / 2 g x 100%
= 0,26 x 100%
= 26 %

Re: Forum kelas pagi

by ALIFFIA RAGIL FITRIANI - Tuesday, 31 October 2023, 9:40 AM

% kadar abu = Wo+abu berat cawan kosong /W1 ×100%
= 37,82g-37,3 g/2g×100%
= 0,52g/2g ×100%
= 26%

Re: Forum kelas pagi

by PUTRI NANDA SAFILATURROHMAH - Tuesday, 31 October 2023, 9:47 AM

diketahui :
cawan kosong: 37,3 gram
cawan dan abu: 37,82 gram
bobot abu: 37,82-37,3 = 0,52

jawab :
%kadar abu = 0,52/2 x 100%
= 26%

Re: Forum kelas pagi

by NADYA RAMADHANTI - Tuesday, 31 October 2023, 9:51 AM

Diketahui:
W0 = 37,3 gram
W1 (berat sampel) = 2 gram
W2 = 37,82 gram

Dijawab:
% kadar abu = Berat abu (W2 - W0) / berat sampel (W1) x 100%
% kadar abu = (37,82 g - 37,3 g) / 2 g x 100%
% kadar abu = 0,52 g / 2 g x 100%
% kadar abu = 0,26 x 100%
% kadar abu = 26%

Jadi persen kadar abu adalah 26%

Re: Forum kelas pagi

by NELITA DWI NOVIYANTI - Tuesday, 31 October 2023, 9:54 AM

diketahui :
W0 = 37,3 gram
W1 = 2 gram
W2 = 37,82 gram

ditanya : % kadar abu dari simplisia?

jawab :
kadar abu (%) = berat abu (W2-W0) / berat sampel (W1) x 100%
kadar abu (%) = (37,82 g -37,3 g) / (2 g x 100%)
kadar abu (%) = 0,52 g / 2 g x 100%
kadar abu (%) = 0,26 x 100%
kadar abu (%) = 26%

Re: Forum kelas pagi

by NIMAS KUSUMANING AYU INDAH PERMADANI - Tuesday, 31 October 2023, 10:01 AM

Diketahui=
Bobot sampel+ cawan = 37,82 g
Bobot cawan kosong = 37,3 g
Bobot sampel awal= 2 g

Ditanya :
% Kadar abu simplisia tersebut?

Jawab:
% Kadar abu = bobot sampel+cawan - bobot cawan kosong / bobot sampel awal × 100%
= 37,82 g - 37,3 g / 2g x 100%
= 0,52 g / 2 g x 100%
= 0,26 x 100%
= 26 %

Jadi, persen kadar abu dari simplisia tersebut ialah 26%

Re: Forum kelas pagi

by DANU PRASTIYO - Tuesday, 31 October 2023, 10:07 AM

Re: Forum kelas pagi

by Luti ANA - Tuesday, 31 October 2023, 10:19 AM

Diketahui:
W0: 37,3 gram ( berat cawan kosong)
W1 : 2 gram (berat simplisia)
W2: 37,82 gram ( cawan+abu)

Ditanya : %kadar abu?
Jawab:
%kadar abu : berat abu (w2-w0)/ berat sample(w1) x 100%
: 37,82 gram -37,3 gram / 2 gram x 100%
: 0,52/2 x100%
: 26%

Re: Forum kelas pagi

by LIESTYA NUR AZIZAH - Tuesday, 31 October 2023, 10:47 AM

Diketahui :
Berat Simplisia = 2 g
Berat Cawan + Abu = 37,82 g
Berat Cawan Kosong = 37,3 g

% Kadar Abu = Berat Cawan + Abu - Berat Cawan Kosong / Berat Simplisia × 100%
% Kadar Abu = 37,82 - 37,3 / 2 × 100%
% Kadar Abu = 0,52/ 2 × 100%
% Kadar Abu = 0,26 × 100%
% Kadar Abu = 26 %

Re: Forum kelas pagi

by TRIYA AGUSTINA SUSANTI - Tuesday, 21 November 2023, 9:31 AM

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